x^2-132x-169=0

Solution for x^2-132x-169=0 equation:

x^2-132x-169=0

a = 1; b = -132; c = -169;
Δ = b2-4ac
Δ = -1322-4·1·(-169)
Δ = 18100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18100}=\sqrt{100*181}=\sqrt{100}*\sqrt{181}=10\sqrt{181}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-10\sqrt{181}}{2*1}=\frac{132-10\sqrt{181}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+10\sqrt{181}}{2*1}=\frac{132+10\sqrt{181}}{2}
$